Base | Representation |
---|---|
bin | 1011111010101101010110… |
… | …0011100001100001000010 |
3 | 1201101122201211210222120220 |
4 | 2332223111203201201002 |
5 | 3204140410134042010 |
6 | 43511313040243510 |
7 | 2521451221516650 |
oct | 276532543414102 |
9 | 51348654728526 |
10 | 13103233112130 |
11 | 41a2060544897 |
12 | 15775b2310596 |
13 | 74082525b055 |
14 | 3342b260ddd0 |
15 | 17aca2660970 |
hex | bead58e1842 |
13103233112130 has 64 divisors (see below), whose sum is σ = 35941582414080. Its totient is φ = 2994917554944.
The previous prime is 13103233112129. The next prime is 13103233112213. The reversal of 13103233112130 is 3121133230131.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13103233112130.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4842832 + ... + 7046948.
It is an arithmetic number, because the mean of its divisors is an integer number (561587225220).
Almost surely, 213103233112130 is an apocalyptic number.
13103233112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13103233112130 is an abundant number, since it is smaller than the sum of its proper divisors (22838349301950).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13103233112130 is a wasteful number, since it uses less digits than its factorization.
13103233112130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2232443.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 13103233112130 its reverse (3121133230131), we get a palindrome (16224366342261).
The spelling of 13103233112130 in words is "thirteen trillion, one hundred three billion, two hundred thirty-three million, one hundred twelve thousand, one hundred thirty".
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