| Base | Representation |
|---|---|
| bin | 10011000100011010101… |
| … | …001000100111101100000 |
| 3 | 11122021101212100220122021 |
| 4 | 103010122221010331200 |
| 5 | 132432210433013440 |
| 6 | 2441554524551224 |
| 7 | 163450142140645 |
| oct | 23043251047540 |
| 9 | 4567355326567 |
| 10 | 1310412001120 |
| 11 | 4658194597a2 |
| 12 | 191b723b2514 |
| 13 | 96757268851 |
| 14 | 475d2317dcc |
| 15 | 2414806784a |
| hex | 1311aa44f60 |
1310412001120 has 96 divisors (see below), whose sum is σ = 3172213025856. Its totient is φ = 511242240000.
The previous prime is 1310412001039. The next prime is 1310412001219. The reversal of 1310412001120 is 211002140131.
It is a super-2 number, since 2×13104120011202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a junction number, because it is equal to n+sod(n) for n = 1310412001094 and 1310412001103.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26221597 + ... + 26271523.
It is an arithmetic number, because the mean of its divisors is an integer number (33043885686).
Almost surely, 21310412001120 is an apocalyptic number.
1310412001120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1310412001120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1586106512928).
1310412001120 is an abundant number, since it is smaller than the sum of its proper divisors (1861801024736).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310412001120 is a wasteful number, since it uses less digits than its factorization.
1310412001120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53984 (or 53976 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1310412001120 its reverse (211002140131), we get a palindrome (1521414141251).
The spelling of 1310412001120 in words is "one trillion, three hundred ten billion, four hundred twelve million, one thousand, one hundred twenty".
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