Base | Representation |
---|---|
bin | 10011000100100001001… |
… | …001110101010011100000 |
3 | 11122021200110221101100121 |
4 | 103010201021311103200 |
5 | 132432421420013130 |
6 | 2442013430330024 |
7 | 163452636556561 |
oct | 23044111652340 |
9 | 4567613841317 |
10 | 1310521251040 |
11 | 465875098891 |
12 | 191ba2ab9914 |
13 | 96773a9a681 |
14 | 47602a36168 |
15 | 24152947d7a |
hex | 131212754e0 |
1310521251040 has 48 divisors (see below), whose sum is σ = 3098113589088. Its totient is φ = 523868668416.
The previous prime is 1310521250993. The next prime is 1310521251119. The reversal of 1310521251040 is 401521250131.
It is a junction number, because it is equal to n+sod(n) for n = 1310521250996 and 1310521251014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2407287 + ... + 2901046.
It is an arithmetic number, because the mean of its divisors is an integer number (64544033106).
Almost surely, 21310521251040 is an apocalyptic number.
1310521251040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310521251040 is an abundant number, since it is smaller than the sum of its proper divisors (1787592338048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310521251040 is a wasteful number, since it uses less digits than its factorization.
1310521251040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5309891 (or 5309883 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 25.
Subtracting from 1310521251040 its reverse (401521250131), we obtain a palindrome (909000000909).
The spelling of 1310521251040 in words is "one trillion, three hundred ten billion, five hundred twenty-one million, two hundred fifty-one thousand, forty".
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