Base | Representation |
---|---|
bin | 1011111010111110001010… |
… | …0111011101001001000010 |
3 | 1201102002101102220010001222 |
4 | 2332233202213131021002 |
5 | 3204224131241321030 |
6 | 43513341013155042 |
7 | 2522001123662330 |
oct | 276574247351102 |
9 | 51362342803058 |
10 | 13107747213890 |
11 | 41a3a676472aa |
12 | 157845202ba82 |
13 | 741094531394 |
14 | 3345bdd4ab50 |
15 | 17ae68ad73e5 |
hex | bebe29dd242 |
13107747213890 has 128 divisors (see below), whose sum is σ = 28498850265600. Its totient is φ = 4240291368960.
The previous prime is 13107747213823. The next prime is 13107747213893. The reversal of 13107747213890 is 9831274770131.
It is not an unprimeable number, because it can be changed into a prime (13107747213893) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1739116202 + ... + 1739123738.
It is an arithmetic number, because the mean of its divisors is an integer number (222647267700).
Almost surely, 213107747213890 is an apocalyptic number.
13107747213890 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13107747213890 is an abundant number, since it is smaller than the sum of its proper divisors (15391103051710).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13107747213890 is a wasteful number, since it uses less digits than its factorization.
13107747213890 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12700.
The product of its (nonzero) digits is 1778112, while the sum is 53.
The spelling of 13107747213890 in words is "thirteen trillion, one hundred seven billion, seven hundred forty-seven million, two hundred thirteen thousand, eight hundred ninety".
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