131100132432 has 80 divisors (see below), whose sum is σ = 360085917312. Its totient is φ = 40958730240.

The previous prime is 131100132431. The next prime is 131100132491. The reversal of 131100132432 is 234231001131.

It is a junction number, because it is equal to n+sod(n) for n = 131100132399 and 131100132408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131100132431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 136668 + ... + 529979.

Almost surely, 2^131100132432 is an apocalyptic number.

131100132432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131100132432 is an abundant number, since it is smaller than the sum of its proper divisors (228985784880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131100132432 is a wasteful number, since it uses less digits than its factorization.

131100132432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 666916 (or 666910 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 131100132432 its reverse (234231001131), we get a palindrome (365331133563).

The spelling of 131100132432 in words is "one hundred thirty-one billion, one hundred million, one hundred thirty-two thousand, four hundred thirty-two".