131102100404040 has 96 divisors (see below), whose sum is σ = 404223496346880. Its totient is φ = 34015680062208.

The previous prime is 131102100404027. The next prime is 131102100404047. The reversal of 131102100404040 is 40404001201131.

131102100404040 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 131102100403998 and 131102100404016.

It is not an unprimeable number, because it can be changed into a prime (131102100404047) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 398855992 + ... + 399184551.

It is an arithmetic number, because the mean of its divisors is an integer number (4210661420280).

Almost surely, 2^{131102100404040} is an apocalyptic number.

131102100404040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131102100404040 is an abundant number, since it is smaller than the sum of its proper divisors (273121395942840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131102100404040 is a wasteful number, since it uses less digits than its factorization.

131102100404040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 798040631 (or 798040590 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 131102100404040 its reverse (40404001201131), we get a palindrome (171506101605171).

The spelling of 131102100404040 in words is "one hundred thirty-one trillion, one hundred two billion, one hundred million, four hundred four thousand, forty".