Base | Representation |
---|---|
bin | 11101110011111011100100… |
… | …111010111100000011110101 |
3 | 122012020012000120101210221221 |
4 | 131303323210322330003311 |
5 | 114141114400124131201 |
6 | 1142504005453310341 |
7 | 36421346614451056 |
oct | 3563734472740365 |
9 | 565205016353857 |
10 | 131112012333301 |
11 | 3885a323973aaa |
12 | 128564777953b1 |
13 | 5820a6ac2288c |
14 | 2453bd8b7472d |
15 | 10257ce9044a1 |
hex | 773ee4ebc0f5 |
131112012333301 has 2 divisors, whose sum is σ = 131112012333302. Its totient is φ = 131112012333300.
The previous prime is 131112012333283. The next prime is 131112012333319. The reversal of 131112012333301 is 103333210211131.
It is a balanced prime because it is at equal distance from previous prime (131112012333283) and next prime (131112012333319).
It can be written as a sum of positive squares in only one way, i.e., 121174853123025 + 9937159210276 = 11007945^2 + 3152326^2 .
It is an emirp because it is prime and its reverse (103333210211131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131112012333301 - 231 = 131109864849653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131112012333371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556006166650 + 65556006166651.
It is an arithmetic number, because the mean of its divisors is an integer number (65556006166651).
Almost surely, 2131112012333301 is an apocalyptic number.
It is an amenable number.
131112012333301 is a deficient number, since it is larger than the sum of its proper divisors (1).
131112012333301 is an equidigital number, since it uses as much as digits as its factorization.
131112012333301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 131112012333301 its reverse (103333210211131), we get a palindrome (234445222544432).
The spelling of 131112012333301 in words is "one hundred thirty-one trillion, one hundred twelve billion, twelve million, three hundred thirty-three thousand, three hundred one".
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