Base | Representation |
---|---|
bin | 11101110011111011110110… |
… | …010000010010110111011101 |
3 | 122012020012202211121112210212 |
4 | 131303323312100102313131 |
5 | 114141120444101110123 |
6 | 1142504054402342205 |
7 | 36421360045346633 |
oct | 3563736620226735 |
9 | 565205684545725 |
10 | 131112303144413 |
11 | 3885a463041768 |
12 | 1285653905a965 |
13 | 5820ab6254066 |
14 | 2453c25635353 |
15 | 10257ea1ea878 |
hex | 773ef6412ddd |
131112303144413 has 2 divisors, whose sum is σ = 131112303144414. Its totient is φ = 131112303144412.
The previous prime is 131112303144307. The next prime is 131112303144469. The reversal of 131112303144413 is 314441303211131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131063527096804 + 48776047609 = 11448298^2 + 220853^2 .
It is a cyclic number.
It is not a de Polignac number, because 131112303144413 - 222 = 131112298950109 is a prime.
It is a super-2 number, since 2×1311123031444132 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131112303144413.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131112303146413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556151572206 + 65556151572207.
It is an arithmetic number, because the mean of its divisors is an integer number (65556151572207).
Almost surely, 2131112303144413 is an apocalyptic number.
It is an amenable number.
131112303144413 is a deficient number, since it is larger than the sum of its proper divisors (1).
131112303144413 is an equidigital number, since it uses as much as digits as its factorization.
131112303144413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 32.
Adding to 131112303144413 its reverse (314441303211131), we get a palindrome (445553606355544).
The spelling of 131112303144413 in words is "one hundred thirty-one trillion, one hundred twelve billion, three hundred three million, one hundred forty-four thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •