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131113131000 = 23353116337579
BaseRepresentation
bin111101000011011110…
…0111001101111111000
3110112102111111011021220
41322012330321233320
54122004430143000
6140122121232040
712321051140145
oct1720674715770
9415374434256
10131113131000
1150671a42a05
12214b1632620
13c4966a2227
1464bb2653cc
1536259401a0
hex1e86f39bf8

131113131000 has 128 divisors (see below), whose sum is σ = 409435603200. Its totient is φ = 34932508800.

The previous prime is 131113130977. The next prime is 131113131013. The reversal of 131113131000 is 131311131.

It is a super-2 number, since 2×1311131310002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3470211 + ... + 3507789.

It is an arithmetic number, because the mean of its divisors is an integer number (3198715650).

Almost surely, 2131113131000 is an apocalyptic number.

131113131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131113131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (204717801600).

131113131000 is an abundant number, since it is smaller than the sum of its proper divisors (278322472200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131113131000 is a wasteful number, since it uses less digits than its factorization.

131113131000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38766 (or 38752 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 131113131000 its reverse (131311131), we get a palindrome (131244442131).

The spelling of 131113131000 in words is "one hundred thirty-one billion, one hundred thirteen million, one hundred thirty-one thousand".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 25 30 40 50 60 75 100 120 125 150 200 250 300 375 500 600 750 1000 1163 1500 2326 3000 3489 4652 5815 6978 9304 11630 13956 17445 23260 27912 29075 34890 37579 46520 58150 69780 75158 87225 112737 116300 139560 145375 150316 174450 187895 225474 232600 290750 300632 348900 375790 436125 450948 563685 581500 697800 751580 872250 901896 939475 1127370 1163000 1503160 1744500 1878950 2254740 2818425 3489000 3757900 4509480 4697375 5636850 7515800 9394750 11273700 14092125 18789500 22547400 28184250 37579000 43704377 56368500 87408754 112737000 131113131 174817508 218521885 262226262 349635016 437043770 524452524 655565655 874087540 1048905048 1092609425 1311131310 1748175080 2185218850 2622262620 3277828275 4370437700 5244525240 5463047125 6555656550 8740875400 10926094250 13111313100 16389141375 21852188500 26222626200 32778282750 43704377000 65556565500 131113131000