131115343243140 has 96 divisors (see below), whose sum is σ = 409465406972160. Its totient is φ = 34831148179968.

The previous prime is 131115343243111. The next prime is 131115343243163. The reversal of 131115343243140 is 41342343511131.

131115343243140 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 15 + 3 + 4 + 324 + 314 + 0 = 666.

It is a super-3 number, since 3×131115343243140³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 131115343243095 and 131115343243104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 461466709 + ... + 461750748.

It is an arithmetic number, because the mean of its divisors is an integer number (4265264655960).

Almost surely, 2^{131115343243140} is an apocalyptic number.

131115343243140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131115343243140 is an abundant number, since it is smaller than the sum of its proper divisors (278350063729020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131115343243140 is a wasteful number, since it uses less digits than its factorization.

131115343243140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 923217738 (or 923217730 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 36.

Adding to 131115343243140 its reverse (41342343511131), we get a palindrome (172457686754271).

The spelling of 131115343243140 in words is "one hundred thirty-one trillion, one hundred fifteen billion, three hundred forty-three million, two hundred forty-three thousand, one hundred forty".