131121111010320 has 120 divisors (see below), whose sum is σ = 449717512772736. Its totient is φ = 34221680027904.

The previous prime is 131121111010283. The next prime is 131121111010387. The reversal of 131121111010320 is 23010111121131.

131121111010320 is a `hidden beast` number, since 1 + 3 + 11 + 211 + 110 + 10 + 320 = 666.

It is a tau number, because it is divible by the number of its divisors (120).

It is a super-2 number, since 2×131121111010320² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 131121111010293 and 131121111010302.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1937334822 + ... + 1937402501.

Almost surely, 2^{131121111010320} is an apocalyptic number.

131121111010320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131121111010320 is an abundant number, since it is smaller than the sum of its proper divisors (318596401762416).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131121111010320 is a wasteful number, since it uses less digits than its factorization.

131121111010320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3874737389 (or 3874737380 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 131121111010320 its reverse (23010111121131), we get a palindrome (154131222131451).

The spelling of 131121111010320 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred eleven million, ten thousand, three hundred twenty".