Base | Representation |
---|---|
bin | 111101000011110001… |
… | …1110100001110100000 |
3 | 110112110012200102102201 |
4 | 1322013203310032200 |
5 | 4122020033111000 |
6 | 140123124022544 |
7 | 12321233634523 |
oct | 1720743641640 |
9 | 415405612381 |
10 | 131123332000 |
11 | 50677780091 |
12 | 214b4b31a54 |
13 | c49883441b |
14 | 64bc75cbba |
15 | 36267a796a |
hex | 1e878f43a0 |
131123332000 has 96 divisors (see below), whose sum is σ = 339126540480. Its totient is φ = 49688812800.
The previous prime is 131123331953. The next prime is 131123332001. The reversal of 131123332000 is 233321131.
It is a super-3 number, since 3×1311233320003 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is not an unprimeable number, because it can be changed into a prime (131123332001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 786654 + ... + 938653.
It is an arithmetic number, because the mean of its divisors is an integer number (3532568130).
Almost surely, 2131123332000 is an apocalyptic number.
131123332000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131123332000 is an abundant number, since it is smaller than the sum of its proper divisors (208003208480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131123332000 is a wasteful number, since it uses less digits than its factorization.
131123332000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1725351 (or 1725333 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 131123332000 its reverse (233321131), we get a palindrome (131356653131).
The spelling of 131123332000 in words is "one hundred thirty-one billion, one hundred twenty-three million, three hundred thirty-two thousand".
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