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1311311089799 is a prime number
BaseRepresentation
bin10011000101010000001…
…110110101000010000111
311122100201112011100102222
4103011100032311002013
5132441031114333144
62442224043322555
7163511340232514
oct23052016650207
94570645140388
101311311089799
1146613aa19397
1219218352045b
139686b603499
14476798b830b
152419be642ee
hex131503b5087

1311311089799 has 2 divisors, whose sum is σ = 1311311089800. Its totient is φ = 1311311089798.

The previous prime is 1311311089729. The next prime is 1311311089801. The reversal of 1311311089799 is 9979801131131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311311089799 - 216 = 1311311024263 is a prime.

It is a Sophie Germain prime.

Together with 1311311089801, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311311089799.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311311089709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655655544899 + 655655544900.

It is an arithmetic number, because the mean of its divisors is an integer number (655655544900).

Almost surely, 21311311089799 is an apocalyptic number.

1311311089799 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311311089799 is an equidigital number, since it uses as much as digits as its factorization.

1311311089799 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 367416, while the sum is 53.

The spelling of 1311311089799 in words is "one trillion, three hundred eleven billion, three hundred eleven million, eighty-nine thousand, seven hundred ninety-nine".