Base | Representation |
---|---|
bin | 1011111011010010011111… |
… | …0000001101000000110000 |
3 | 1201102121110121020011020210 |
4 | 2332310213300031000300 |
5 | 3204321314214233240 |
6 | 43520042154304120 |
7 | 2522253241526205 |
oct | 276644760150060 |
9 | 51377417204223 |
10 | 13113202102320 |
11 | 41a63067a9761 |
12 | 1579514a28040 |
13 | 7417536aba08 |
14 | 33497a5bdcac |
15 | 17b187945780 |
hex | bed27c0d030 |
13113202102320 has 160 divisors (see below), whose sum is σ = 42455168266752. Its totient is φ = 3341914177536.
The previous prime is 13113202102307. The next prime is 13113202102339. The reversal of 13113202102320 is 2320120231131.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5334387 + ... + 7394733.
Almost surely, 213113202102320 is an apocalyptic number.
13113202102320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13113202102320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21227584133376).
13113202102320 is an abundant number, since it is smaller than the sum of its proper divisors (29341966164432).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13113202102320 is a wasteful number, since it uses less digits than its factorization.
13113202102320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2061539 (or 2061533 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13113202102320 its reverse (2320120231131), we get a palindrome (15433322333451).
The spelling of 13113202102320 in words is "thirteen trillion, one hundred thirteen billion, two hundred two million, one hundred two thousand, three hundred twenty".
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