Base | Representation |
---|---|
bin | 11101110100001110010011… |
… | …000001101010100001000100 |
3 | 122012022002220102201200222112 |
4 | 131310032103001222201010 |
5 | 114141432031434414340 |
6 | 1142521132224520152 |
7 | 36422661003143405 |
oct | 3564162301524104 |
9 | 565262812650875 |
10 | 131132113201220 |
11 | 388678a932763a |
12 | 1285a347480058 |
13 | 5822922486071 |
14 | 2454b845d59ac |
15 | 10260a9447065 |
hex | 77439306a844 |
131132113201220 has 96 divisors (see below), whose sum is σ = 294412872337920. Its totient is φ = 48939600061440.
The previous prime is 131132113201147. The next prime is 131132113201249. The reversal of 131132113201220 is 22102311231131.
It is a happy number.
It is a super-2 number, since 2×1311321132012202 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 102699434 + ... + 103968446.
It is an arithmetic number, because the mean of its divisors is an integer number (3066800753520).
Almost surely, 2131132113201220 is an apocalyptic number.
131132113201220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131132113201220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147206436168960).
131132113201220 is an abundant number, since it is smaller than the sum of its proper divisors (163280759136700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131132113201220 is a wasteful number, since it uses less digits than its factorization.
131132113201220 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1274565 (or 1274563 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 131132113201220 its reverse (22102311231131), we get a palindrome (153234424432351).
The spelling of 131132113201220 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, one hundred thirteen million, two hundred one thousand, two hundred twenty".
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