Base | Representation |
---|---|
bin | 1011111011010010111101… |
… | …1001010000000000110110 |
3 | 1201102121210112110102120020 |
4 | 2332310233121100000312 |
5 | 3204322100024144110 |
6 | 43520103014150010 |
7 | 2522256356314206 |
oct | 276645731200066 |
9 | 51377715412506 |
10 | 13113330303030 |
11 | 41a6372101861 |
12 | 157954b952306 |
13 | 741774117519 |
14 | 33498d632406 |
15 | 17b193d1ad70 |
hex | bed2f650036 |
13113330303030 has 64 divisors (see below), whose sum is σ = 31516212127680. Its totient is φ = 3491976144384.
The previous prime is 13113330303023. The next prime is 13113330303043. The reversal of 13113330303030 is 3030303331131.
13113330303030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 174720672 + ... + 174795708.
It is an arithmetic number, because the mean of its divisors is an integer number (492440814495).
Almost surely, 213113330303030 is an apocalyptic number.
13113330303030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13113330303030 is an abundant number, since it is smaller than the sum of its proper divisors (18402881824650).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13113330303030 is a wasteful number, since it uses less digits than its factorization.
13113330303030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83153.
The product of its (nonzero) digits is 2187, while the sum is 24.
Adding to 13113330303030 its reverse (3030303331131), we get a palindrome (16143633634161).
The spelling of 13113330303030 in words is "thirteen trillion, one hundred thirteen billion, three hundred thirty million, three hundred three thousand, thirty".
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