13114134020 has 96 divisors (see below), whose sum is σ = 32576705280. Its totient is φ = 4387806720.

The previous prime is 13114134013. The next prime is 13114134031. The reversal of 13114134020 is 2043141131.

It is a super-2 number, since 2×13114134020² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13114133983 and 13114134001.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 55910 + ... + 171330.

It is an arithmetic number, because the mean of its divisors is an integer number (339340680).

Almost surely, 2^13114134020 is an apocalyptic number.

13114134020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13114134020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16288352640).

13114134020 is an abundant number, since it is smaller than the sum of its proper divisors (19462571260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114134020 is a wasteful number, since it uses less digits than its factorization.

13114134020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115485 (or 115483 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13114134020 its reverse (2043141131), we get a palindrome (15157275151).

The spelling of 13114134020 in words is "thirteen billion, one hundred fourteen million, one hundred thirty-four thousand, twenty".