13114313040 has 80 divisors (see below), whose sum is σ = 40683431808. Its totient is φ = 3494650368.

The previous prime is 13114313021. The next prime is 13114313053. The reversal of 13114313040 is 4031341131.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×13114313040² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13114312998 and 13114313016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 329917 + ... + 367523.

Almost surely, 2^13114313040 is an apocalyptic number.

13114313040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13114313040 is an abundant number, since it is smaller than the sum of its proper divisors (27569118768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114313040 is a wasteful number, since it uses less digits than its factorization.

13114313040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39076 (or 39070 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13114313040 its reverse (4031341131), we get a palindrome (17145654171).

The spelling of 13114313040 in words is "thirteen billion, one hundred fourteen million, three hundred thirteen thousand, forty".