13114334310040 has 64 divisors (see below), whose sum is σ = 30227635740960. Its totient is φ = 5117671418880.

The previous prime is 13114334310023. The next prime is 13114334310079. The reversal of 13114334310040 is 4001343341131.

It is a junction number, because it is equal to n+sod(n) for n = 13114334309990 and 13114334310008.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116126082 + ... + 116238958.

Almost surely, 2^{13114334310040} is an apocalyptic number.

13114334310040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13114334310040 is an abundant number, since it is smaller than the sum of its proper divisors (17113301430920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114334310040 is a wasteful number, since it uses less digits than its factorization.

13114334310040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183772 (or 183768 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13114334310040 its reverse (4001343341131), we get a palindrome (17115677651171).

The spelling of 13114334310040 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, three hundred ten thousand, forty".