Base | Representation |
---|---|
bin | 111101000100011001… |
… | …1110011011110001111 |
3 | 110112111200010201201021 |
4 | 1322020303303132033 |
5 | 4122040420103211 |
6 | 140125153255011 |
7 | 12321610106134 |
oct | 1721063633617 |
9 | 415450121637 |
10 | 131144300431 |
11 | 506885a1a71 |
12 | 214bbb64467 |
13 | c49cc96591 |
14 | 64c145a58b |
15 | 362854a771 |
hex | 1e88cf378f |
131144300431 has 2 divisors, whose sum is σ = 131144300432. Its totient is φ = 131144300430.
The previous prime is 131144300429. The next prime is 131144300437. The reversal of 131144300431 is 134003441131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131144300431 - 21 = 131144300429 is a prime.
It is a super-2 number, since 2×1311443004312 (a number of 23 digits) contains 22 as substring.
Together with 131144300429, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 131144300396 and 131144300405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131144300437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65572150215 + 65572150216.
It is an arithmetic number, because the mean of its divisors is an integer number (65572150216).
Almost surely, 2131144300431 is an apocalyptic number.
131144300431 is a deficient number, since it is larger than the sum of its proper divisors (1).
131144300431 is an equidigital number, since it uses as much as digits as its factorization.
131144300431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 131144300431 its reverse (134003441131), we get a palindrome (265147741562).
The spelling of 131144300431 in words is "one hundred thirty-one billion, one hundred forty-four million, three hundred thousand, four hundred thirty-one".
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