Base | Representation |
---|---|
bin | 10011000101011101010… |
… | …011111100001100010010 |
3 | 11122101021211002020211000 |
4 | 103011131103330030102 |
5 | 132442003304034100 |
6 | 2442301523002430 |
7 | 163516643411511 |
oct | 23053523741422 |
9 | 4571254066730 |
10 | 1311530533650 |
11 | 466242881847 |
12 | 192224b09416 |
13 | 968a4c07a0c |
14 | 4769aabc678 |
15 | 241b135e900 |
hex | 1315d4fc312 |
1311530533650 has 96 divisors (see below), whose sum is σ = 3616825651200. Its totient is φ = 349467566400.
The previous prime is 1311530533631. The next prime is 1311530533673. The reversal of 1311530533650 is 563350351131.
1311530533650 is a `hidden beast` number, since 1 + 3 + 1 + 15 + 305 + 336 + 5 + 0 = 666.
It is a super-2 number, since 2×13115305336502 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1346860 + ... + 2106440.
It is an arithmetic number, because the mean of its divisors is an integer number (37675267200).
Almost surely, 21311530533650 is an apocalyptic number.
1311530533650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311530533650, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1808412825600).
1311530533650 is an abundant number, since it is smaller than the sum of its proper divisors (2305295117550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311530533650 is a wasteful number, since it uses less digits than its factorization.
1311530533650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 760881 (or 760870 counting only the distinct ones).
The product of its (nonzero) digits is 60750, while the sum is 36.
Adding to 1311530533650 its reverse (563350351131), we get a palindrome (1874880884781).
The spelling of 1311530533650 in words is "one trillion, three hundred eleven billion, five hundred thirty million, five hundred thirty-three thousand, six hundred fifty".
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