Base | Representation |
---|---|
bin | 11101110101011001101010… |
… | …111000001011000110101000 |
3 | 122012120211210122022102022101 |
4 | 131311121222320023012220 |
5 | 114144243303231100430 |
6 | 1143022235032503144 |
7 | 36431554356462463 |
oct | 3565315270130650 |
9 | 565524718272271 |
10 | 131213044003240 |
11 | 38899159693a91 |
12 | 12871b72b4aab4 |
13 | 582a44c3aa5b4 |
14 | 2458a60c282da |
15 | 10282444c8dca |
hex | 77566ae0b1a8 |
131213044003240 has 64 divisors (see below), whose sum is σ = 300317049446400. Its totient is φ = 51581234195712.
The previous prime is 131213044003147. The next prime is 131213044003247. The reversal of 131213044003240 is 42300440312131.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 131213044003199 and 131213044003208.
It is not an unprimeable number, because it can be changed into a prime (131213044003247) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 697194 + ... + 16214566.
It is an arithmetic number, because the mean of its divisors is an integer number (4692453897600).
Almost surely, 2131213044003240 is an apocalyptic number.
131213044003240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131213044003240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (150158524723200).
131213044003240 is an abundant number, since it is smaller than the sum of its proper divisors (169104005443160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131213044003240 is a wasteful number, since it uses less digits than its factorization.
131213044003240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15521026 (or 15521022 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 131213044003240 its reverse (42300440312131), we get a palindrome (173513484315371).
The spelling of 131213044003240 in words is "one hundred thirty-one trillion, two hundred thirteen billion, forty-four million, three thousand, two hundred forty".
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