131213131100032 has 64 divisors (see below), whose sum is σ = 261990542223360. Its totient is φ = 65458700285440.

The previous prime is 131213131099979. The next prime is 131213131100039. The reversal of 131213131100032 is 230001131312131.

It is a tau number, because it is divible by the number of its divisors (64).

It is a junction number, because it is equal to n+sod(n) for n = 131213131099976 and 131213131100012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131213131100039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 291578433 + ... + 292028095.

It is an arithmetic number, because the mean of its divisors is an integer number (4093602222240).

Almost surely, 2^{131213131100032} is an apocalyptic number.

It is an amenable number.

131213131100032 is a deficient number, since it is larger than the sum of its proper divisors (130777411123328).

131213131100032 is an equidigital number, since it uses as much as digits as its factorization.

131213131100032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 454811 (or 454799 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 131213131100032 its reverse (230001131312131), we get a palindrome (361214262412163).

The spelling of 131213131100032 in words is "one hundred thirty-one trillion, two hundred thirteen billion, one hundred thirty-one million, one hundred thousand, thirty-two".