Base | Representation |
---|---|
bin | 11000011100001100… |
… | …10011001001110110 |
3 | 1020212110021220220120 |
4 | 30032012103021312 |
5 | 203333041343410 |
6 | 10010005512410 |
7 | 643106231202 |
oct | 141606231166 |
9 | 36773256816 |
10 | 13121434230 |
11 | 5623786823 |
12 | 2662412706 |
13 | 13115ab688 |
14 | 8c6939b02 |
15 | 51be3c570 |
hex | 30e193276 |
13121434230 has 16 divisors (see below), whose sum is σ = 31491442224. Its totient is φ = 3499049120.
The previous prime is 13121434223. The next prime is 13121434237. The reversal of 13121434230 is 3243412131.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (13121434223) and next prime (13121434237).
It is a self number, because there is not a number n which added to its sum of digits gives 13121434230.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121434237) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218690541 + ... + 218690600.
It is an arithmetic number, because the mean of its divisors is an integer number (1968215139).
Almost surely, 213121434230 is an apocalyptic number.
13121434230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13121434230 is an abundant number, since it is smaller than the sum of its proper divisors (18370007994).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13121434230 is a wasteful number, since it uses less digits than its factorization.
13121434230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437381151.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13121434230 its reverse (3243412131), we get a palindrome (16364846361).
The spelling of 13121434230 in words is "thirteen billion, one hundred twenty-one million, four hundred thirty-four thousand, two hundred thirty".
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