1312204022130 has 64 divisors (see below), whose sum is σ = 3338407001088. Its totient is φ = 328955750400.

The previous prime is 1312204022123. The next prime is 1312204022159. The reversal of 1312204022130 is 312204022131.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1312204022097 and 1312204022106.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1050571 + ... + 1930830.

It is an arithmetic number, because the mean of its divisors is an integer number (52162609392).

Almost surely, 2^{1312204022130} is an apocalyptic number.

1312204022130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1312204022130 is an abundant number, since it is smaller than the sum of its proper divisors (2026202978958).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312204022130 is a wasteful number, since it uses less digits than its factorization.

1312204022130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2982291.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1312204022130 its reverse (312204022131), we get a palindrome (1624408044261).

Subtracting from 1312204022130 its reverse (312204022131), we obtain a palindrome (999999999999).

The spelling of 1312204022130 in words is "one trillion, three hundred twelve billion, two hundred four million, twenty-two thousand, one hundred thirty".