Base | Representation |
---|---|
bin | 111101000110101101… |
… | …0000010111100010010 |
3 | 110112201001021112020221 |
4 | 1322031122002330102 |
5 | 4122220141343010 |
6 | 140140550423254 |
7 | 12323534533543 |
oct | 1721532027422 |
9 | 415631245227 |
10 | 131221434130 |
11 | 50718095726 |
12 | 21521961b2a |
13 | c4b2c62117 |
14 | 64cb7b84ca |
15 | 36301d4dda |
hex | 1e8d682f12 |
131221434130 has 128 divisors (see below), whose sum is σ = 266823486720. Its totient is φ = 46169948160.
The previous prime is 131221434121. The next prime is 131221434199. The reversal of 131221434130 is 31434122131.
It is a junction number, because it is equal to n+sod(n) for n = 131221434095 and 131221434104.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 153834784 + ... + 153835636.
It is an arithmetic number, because the mean of its divisors is an integer number (2084558490).
Almost surely, 2131221434130 is an apocalyptic number.
131221434130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131221434130 is an abundant number, since it is smaller than the sum of its proper divisors (135602052590).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131221434130 is a wasteful number, since it uses less digits than its factorization.
131221434130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1484.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 131221434130 its reverse (31434122131), we get a palindrome (162655556261).
The spelling of 131221434130 in words is "one hundred thirty-one billion, two hundred twenty-one million, four hundred thirty-four thousand, one hundred thirty".
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