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131230211014140 = 22357364943856169
BaseRepresentation
bin11101110101101001101010…
…000111000111110111111100
3122012122111010001001221002220
4131311221222013013313330
5114200033433004423030
61143034154321245340
736433032651613110
oct3565515207076774
9565574101057086
10131230211014140
11388a5468a533a7
1212875364193850
13582bc56b77604
14245980cb7d740
1510288eb690a10
hex775a6a1c7dfc

131230211014140 has 96 divisors (see below), whose sum is σ = 419938316421120. Its totient is φ = 29995359576576.

The previous prime is 131230211014099. The next prime is 131230211014141. The reversal of 131230211014140 is 41410112032131.

131230211014140 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1312302110141402 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131230211014140.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131230211014141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 152847976 + ... + 153704144.

It is an arithmetic number, because the mean of its divisors is an integer number (4374357462720).

Almost surely, 2131230211014140 is an apocalyptic number.

131230211014140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131230211014140 is an abundant number, since it is smaller than the sum of its proper divisors (288708105406980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131230211014140 is a wasteful number, since it uses less digits than its factorization.

131230211014140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1221131 (or 1221129 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 131230211014140 its reverse (41410112032131), we get a palindrome (172640323046271).

The spelling of 131230211014140 in words is "one hundred thirty-one trillion, two hundred thirty billion, two hundred eleven million, fourteen thousand, one hundred forty".

Divisors: 1 2 3 4 5 6 7 10 12 14 15 20 21 28 30 35 42 60 70 84 105 140 210 420 364943 729886 856169 1094829 1459772 1712338 1824715 2189658 2554601 2568507 3424676 3649430 4280845 4379316 5109202 5137014 5474145 5993183 7298860 7663803 8561690 10218404 10274028 10948290 11986366 12773005 12842535 15327606 17123380 17979549 21896580 23972732 25546010 25685070 29965915 30655212 35959098 38319015 51092020 51370140 59931830 71918196 76638030 89897745 119863660 153276060 179795490 359590980 312452883367 624905766734 937358650101 1249811533468 1562264416835 1874717300202 2187170183569 3124528833670 3749434600404 4374340367138 4686793250505 6249057667340 6561510550707 8748680734276 9373586501010 10935850917845 13123021101414 18747173002020 21871701835690 26246042202828 32807552753535 43743403671380 65615105507070 131230211014140