Base | Representation |
---|---|
bin | 1011111011111011100000… |
… | …0111010101110010110100 |
3 | 1201110122220001002121020220 |
4 | 2332332320013111302310 |
5 | 3210011342242140200 |
6 | 43525103010054340 |
7 | 2523123154353234 |
oct | 276767007256264 |
9 | 51418801077226 |
10 | 13124214021300 |
11 | 41aaa47738448 |
12 | 157b68887a3b0 |
13 | 7427b9c1a4c5 |
14 | 335302cb3cc4 |
15 | 17b5ce58b4a0 |
hex | befb81d5cb4 |
13124214021300 has 72 divisors (see below), whose sum is σ = 37983854773536. Its totient is φ = 3498764703360.
The previous prime is 13124214021271. The next prime is 13124214021301. The reversal of 13124214021300 is 312041242131.
It is a super-3 number, since 3×131242140213003 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13124214021301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5385034 + ... + 7432833.
Almost surely, 213124214021300 is an apocalyptic number.
13124214021300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13124214021300 is an abundant number, since it is smaller than the sum of its proper divisors (24859640752236).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13124214021300 is a wasteful number, since it uses less digits than its factorization.
13124214021300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12821297 (or 12821290 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13124214021300 its reverse (312041242131), we get a palindrome (13436255263431).
The spelling of 13124214021300 in words is "thirteen trillion, one hundred twenty-four billion, two hundred fourteen million, twenty-one thousand, three hundred".
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