Base | Representation |
---|---|
bin | 1011111100001000100111… |
… | …1011011010111111111010 |
3 | 1201110222222100202202020210 |
4 | 2333002021323122333322 |
5 | 3210041044413043000 |
6 | 43530444153531550 |
7 | 2523306326551122 |
oct | 277021173327772 |
9 | 51428870682223 |
10 | 13127734112250 |
11 | 420149373791a |
12 | 15802ab713bb6 |
13 | 742c2b29c764 |
14 | 3355585c1c82 |
15 | 17b738616350 |
hex | bf089edaffa |
13127734112250 has 96 divisors (see below), whose sum is σ = 33478828373952. Its totient is φ = 3426245066400.
The previous prime is 13127734112249. The next prime is 13127734112261. The reversal of 13127734112250 is 5221143772131.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13127734112199 and 13127734112208.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2305144 + ... + 5618643.
It is an arithmetic number, because the mean of its divisors is an integer number (348737795562).
Almost surely, 213127734112250 is an apocalyptic number.
13127734112250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13127734112250 is an abundant number, since it is smaller than the sum of its proper divisors (20351094261702).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13127734112250 is an equidigital number, since it uses as much as digits as its factorization.
13127734112250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7923901 (or 7923844 counting only the distinct ones).
The product of its (nonzero) digits is 70560, while the sum is 39.
Adding to 13127734112250 its reverse (5221143772131), we get a palindrome (18348877884381).
The spelling of 13127734112250 in words is "thirteen trillion, one hundred twenty-seven billion, seven hundred thirty-four million, one hundred twelve thousand, two hundred fifty".
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