Base | Representation |
---|---|
bin | 1011111100010001001110… |
… | …1100110111111101110110 |
3 | 1201111012221110011011222212 |
4 | 2333010103230313331312 |
5 | 3210110313130221200 |
6 | 43531505404053422 |
7 | 2523420524520011 |
oct | 277042354677566 |
9 | 51435843134885 |
10 | 13130045554550 |
11 | 420246a463711 |
12 | 1580835834272 |
13 | 74320911cab2 |
14 | 3356d758c378 |
15 | 17b8214e8035 |
hex | bf113b37f76 |
13130045554550 has 96 divisors (see below), whose sum is σ = 25613022161664. Its totient is φ = 4998193200000.
The previous prime is 13130045554537. The next prime is 13130045554567. The reversal of 13130045554550 is 5545554003131.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13130045554498 and 13130045554507.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 921334925 + ... + 921349175.
It is an arithmetic number, because the mean of its divisors is an integer number (266802314184).
Almost surely, 213130045554550 is an apocalyptic number.
13130045554550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13130045554550 is a deficient number, since it is larger than the sum of its proper divisors (12482976607114).
13130045554550 is a wasteful number, since it uses less digits than its factorization.
13130045554550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18294 (or 18289 counting only the distinct ones).
The product of its (nonzero) digits is 450000, while the sum is 41.
Adding to 13130045554550 its reverse (5545554003131), we get a palindrome (18675599557681).
The spelling of 13130045554550 in words is "thirteen trillion, one hundred thirty billion, forty-five million, five hundred fifty-four thousand, five hundred fifty".
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