Base | Representation |
---|---|
bin | 11101110110101100111010… |
… | …111000100101111101101110 |
3 | 122012220101112022201001022121 |
4 | 131312230322320211331232 |
5 | 114202224340334320420 |
6 | 1143131301031503154 |
7 | 36441200460441610 |
oct | 3566547270457556 |
9 | 565811468631277 |
10 | 131302433120110 |
11 | 3892305a4a358a |
12 | 1288735b227aba |
13 | 58359c6793465 |
14 | 245d100948db0 |
15 | 102a726dd82aa |
hex | 776b3ae25f6e |
131302433120110 has 128 divisors (see below), whose sum is σ = 280579603968000. Its totient is φ = 43285885429248.
The previous prime is 131302433120107. The next prime is 131302433120119. The reversal of 131302433120110 is 11021334203131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131302433120119) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 528087801 + ... + 528336379.
It is an arithmetic number, because the mean of its divisors is an integer number (2192028156000).
Almost surely, 2131302433120110 is an apocalyptic number.
131302433120110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131302433120110 is an abundant number, since it is smaller than the sum of its proper divisors (149277170847890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131302433120110 is a wasteful number, since it uses less digits than its factorization.
131302433120110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 249698.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 131302433120110 its reverse (11021334203131), we get a palindrome (142323767323241).
The spelling of 131302433120110 in words is "one hundred thirty-one trillion, three hundred two billion, four hundred thirty-three million, one hundred twenty thousand, one hundred ten".
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