Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …101010011001100111111110 |
3 | 122012221012220120000202202120 |
4 | 131312310333222121213332 |
5 | 114202400114411021342 |
6 | 1143135253230103410 |
7 | 36441625356202452 |
oct | 3566647752314776 |
9 | 565835816022676 |
10 | 131311103220222 |
11 | 389267a9549082 |
12 | 12888b7a94ab66 |
13 | 5836778aa7403 |
14 | 245d6c4206662 |
15 | 102aa8314baec |
hex | 776d3fa999fe |
131311103220222 has 64 divisors (see below), whose sum is σ = 287047141632000. Its totient is φ = 39865838653440.
The previous prime is 131311103220161. The next prime is 131311103220259. The reversal of 131311103220222 is 222022301113131.
It is a junction number, because it is equal to n+sod(n) for n = 131311103220192 and 131311103220201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 145156029 + ... + 146057847.
It is an arithmetic number, because the mean of its divisors is an integer number (4485111588000).
Almost surely, 2131311103220222 is an apocalyptic number.
131311103220222 is an abundant number, since it is smaller than the sum of its proper divisors (155736038411778).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131311103220222 is a wasteful number, since it uses less digits than its factorization.
131311103220222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 947921.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 131311103220222 its reverse (222022301113131), we get a palindrome (353333404333353).
The spelling of 131311103220222 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred three million, two hundred twenty thousand, two hundred twenty-two".
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