Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …101010110010010011101000 |
3 | 122012221012220120012220102221 |
4 | 131312310333222302103220 |
5 | 114202400114422240240 |
6 | 1143135253232203424 |
7 | 36441625360103266 |
oct | 3566647752622350 |
9 | 565835816186387 |
10 | 131311103321320 |
11 | 389267a960802a |
12 | 12888b7a999574 |
13 | 5836778b11430 |
14 | 245d6c4231436 |
15 | 102aa8316ba4a |
hex | 776d3fab24e8 |
131311103321320 has 32 divisors (see below), whose sum is σ = 318176904202920. Its totient is φ = 48484099687680.
The previous prime is 131311103321309. The next prime is 131311103321353. The reversal of 131311103321320 is 23123301113131.
It can be written as a sum of positive squares in 4 ways, for example, as 46292265960964 + 85018837360356 = 6803842^2 + 9220566^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 126260675751 + ... + 126260676790.
Almost surely, 2131311103321320 is an apocalyptic number.
131311103321320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131311103321320 is an abundant number, since it is smaller than the sum of its proper divisors (186865800881600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131311103321320 is a wasteful number, since it uses less digits than its factorization.
131311103321320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252521352565 (or 252521352561 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 131311103321320 its reverse (23123301113131), we get a palindrome (154434404434451).
The spelling of 131311103321320 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred three million, three hundred twenty-one thousand, three hundred twenty".
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