131311421040 has 40 divisors (see below), whose sum is σ = 407065405968. Its totient is φ = 35016378880.

The previous prime is 131311421039. The next prime is 131311421071. The reversal of 131311421040 is 40124113131.

It is a tau number, because it is divible by the number of its divisors (40).

It is a junction number, because it is equal to n+sod(n) for n = 131311420998 and 131311421016.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 273565221 + ... + 273565700.

Almost surely, 2^131311421040 is an apocalyptic number.

131311421040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131311421040 is an abundant number, since it is smaller than the sum of its proper divisors (275753984928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131311421040 is a wasteful number, since it uses less digits than its factorization.

131311421040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 547130937 (or 547130931 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 131311421040 its reverse (40124113131), we get a palindrome (171435534171).

The spelling of 131311421040 in words is "one hundred thirty-one billion, three hundred eleven million, four hundred twenty-one thousand, forty".