Base | Representation |
---|---|
bin | 11101110110110110111100… |
… | …110101100111010111100100 |
3 | 122012221102022220201111020020 |
4 | 131312312330311213113210 |
5 | 114202413420021441400 |
6 | 1143140241450235140 |
7 | 36442031406531345 |
oct | 3566667465472744 |
9 | 565842286644206 |
10 | 131313203312100 |
11 | 38927686a3a1a7 |
12 | 12889466125ab0 |
13 | 5836a21bc8024 |
14 | 245d8430b80cc |
15 | 102ab576d12a0 |
hex | 776dbcd675e4 |
131313203312100 has 72 divisors (see below), whose sum is σ = 379979101551840. Its totient is φ = 35012593082880.
The previous prime is 131313203312063. The next prime is 131313203312101. The reversal of 131313203312100 is 1213302313131.
It is not an unprimeable number, because it can be changed into a prime (131313203312101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24162277 + ... + 29093676.
Almost surely, 2131313203312100 is an apocalyptic number.
131313203312100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131313203312100 is an abundant number, since it is smaller than the sum of its proper divisors (248665898239740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131313203312100 is a wasteful number, since it uses less digits than its factorization.
131313203312100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53264189 (or 53264182 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 131313203312100 its reverse (1213302313131), we get a palindrome (132526505625231).
The spelling of 131313203312100 in words is "one hundred thirty-one trillion, three hundred thirteen billion, two hundred three million, three hundred twelve thousand, one hundred".
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