Base | Representation |
---|---|
bin | 10011000111000010000… |
… | …101101101001110001010 |
3 | 11122112122122120010202210 |
4 | 103013002011231032022 |
5 | 133003434123114010 |
6 | 2443141402005550 |
7 | 163606563611664 |
oct | 23070205551612 |
9 | 4575578503683 |
10 | 1313221301130 |
11 | 466a30209442 |
12 | 1926171a68b6 |
13 | 96ab42a0b4b |
14 | 477bb47d534 |
15 | 2425e9dcb20 |
hex | 131c216d38a |
1313221301130 has 64 divisors (see below), whose sum is σ = 3288916493568. Its totient is φ = 334950950400.
The previous prime is 1313221301011. The next prime is 1313221301143. The reversal of 1313221301130 is 311031223131.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1313221301097 and 1313221301106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24797680 + ... + 24850580.
It is an arithmetic number, because the mean of its divisors is an integer number (51389320212).
Almost surely, 21313221301130 is an apocalyptic number.
1313221301130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1313221301130 is an abundant number, since it is smaller than the sum of its proper divisors (1975695192438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313221301130 is a wasteful number, since it uses less digits than its factorization.
1313221301130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88911.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 1313221301130 its reverse (311031223131), we get a palindrome (1624252524261).
The spelling of 1313221301130 in words is "one trillion, three hundred thirteen billion, two hundred twenty-one million, three hundred one thousand, one hundred thirty".
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