Base | Representation |
---|---|
bin | 11101110111000000010000… |
… | …110011101000010001000110 |
3 | 122012222101010202001002021021 |
4 | 131313000100303220101012 |
5 | 114203044404203342410 |
6 | 1143145013545141354 |
7 | 36442534240220524 |
oct | 3567002063502106 |
9 | 565871122032237 |
10 | 131323202012230 |
11 | 38930947a46638 |
12 | 1288b39678a85a |
13 | 583795654b937 |
14 | 2460110dbd314 |
15 | 102b0403d3eda |
hex | 777010ce8446 |
131323202012230 has 32 divisors (see below), whose sum is σ = 236906708701824. Its totient is φ = 52412737086336.
The previous prime is 131323202012147. The next prime is 131323202012231. The reversal of 131323202012230 is 32210202323131.
It is a junction number, because it is equal to n+sod(n) for n = 131323202012195 and 131323202012204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131323202012231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2567667 + ... + 16408513.
It is an arithmetic number, because the mean of its divisors is an integer number (7403334646932).
Almost surely, 2131323202012230 is an apocalyptic number.
131323202012230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131323202012230 is a deficient number, since it is larger than the sum of its proper divisors (105583506689594).
131323202012230 is a wasteful number, since it uses less digits than its factorization.
131323202012230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13842960.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131323202012230 its reverse (32210202323131), we get a palindrome (163533404335361).
The spelling of 131323202012230 in words is "one hundred thirty-one trillion, three hundred twenty-three billion, two hundred two million, twelve thousand, two hundred thirty".
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