Base | Representation |
---|---|
bin | 11101110111001011011100… |
… | …110010101010010110110100 |
3 | 122020000112010220011202020101 |
4 | 131313023130302222112310 |
5 | 114203244004321322200 |
6 | 1143154321533043444 |
7 | 36443441020424302 |
oct | 3567133462522664 |
9 | 566015126152211 |
10 | 131335214245300 |
11 | 38935a515a308a |
12 | 12891789626584 |
13 | 5838b1c0a7560 |
14 | 24609304a3272 |
15 | 102b4e4c6e26a |
hex | 7772dccaa5b4 |
131335214245300 has 144 divisors (see below), whose sum is σ = 308711938046400. Its totient is φ = 48210059980800.
The previous prime is 131335214245273. The next prime is 131335214245307. The reversal of 131335214245300 is 3542412533131.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 131335214245300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131335214245307) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 960749955 + ... + 960886645.
It is an arithmetic number, because the mean of its divisors is an integer number (2143832903100).
Almost surely, 2131335214245300 is an apocalyptic number.
131335214245300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131335214245300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154355969023200).
131335214245300 is an abundant number, since it is smaller than the sum of its proper divisors (177376723801100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131335214245300 is a wasteful number, since it uses less digits than its factorization.
131335214245300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 141026 (or 141019 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 131335214245300 its reverse (3542412533131), we get a palindrome (134877626778431).
The spelling of 131335214245300 in words is "one hundred thirty-one trillion, three hundred thirty-five billion, two hundred fourteen million, two hundred forty-five thousand, three hundred".
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