Base | Representation |
---|---|
bin | 1011111100110110101100… |
… | …0000011000110000110000 |
3 | 1201112011220011210012202121 |
4 | 2333031223000120300300 |
5 | 3210241411124101000 |
6 | 43540251222324024 |
7 | 2524224635006203 |
oct | 277155300306060 |
9 | 51464804705677 |
10 | 13140100222000 |
11 | 420675a017134 |
12 | 1582780b89614 |
13 | 74414c23ac6b |
14 | 335dacaa193a |
15 | 17bc0e0a3b1a |
hex | bf36b018c30 |
13140100222000 has 40 divisors (see below), whose sum is σ = 31772762341632. Its totient is φ = 5256040088000.
The previous prime is 13140100221953. The next prime is 13140100222001. The reversal of 13140100222000 is 22200104131.
It is a tau number, because it is divible by the number of its divisors (40).
It is a Harshad number since it is a multiple of its sum of digits (16).
It is not an unprimeable number, because it can be changed into a prime (13140100222001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3285023056 + ... + 3285027055.
Almost surely, 213140100222000 is an apocalyptic number.
13140100222000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13140100222000 is an abundant number, since it is smaller than the sum of its proper divisors (18632662119632).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13140100222000 is an equidigital number, since it uses as much as digits as its factorization.
13140100222000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6570050134 (or 6570050118 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 13140100222000 its reverse (22200104131), we get a palindrome (13162300326131).
The spelling of 13140100222000 in words is "thirteen trillion, one hundred forty billion, one hundred million, two hundred twenty-two thousand".
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