Base | Representation |
---|---|
bin | 1011111100110111001011… |
… | …0111101010010111100000 |
3 | 1201112012020101000222110001 |
4 | 2333031302313222113200 |
5 | 3210242143412340134 |
6 | 43540312254145344 |
7 | 2524231126260310 |
oct | 277156267522740 |
9 | 51465211028401 |
10 | 13140232152544 |
11 | 4206817537542 |
12 | 15827b91b2254 |
13 | 744170681383 |
14 | 335dc2405440 |
15 | 17bc1a964414 |
hex | bf372dea5e0 |
13140232152544 has 96 divisors (see below), whose sum is σ = 30855688758720. Its totient is φ = 5389219110912.
The previous prime is 13140232152539. The next prime is 13140232152587. The reversal of 13140232152544 is 44525123204131.
It is a super-2 number, since 2×131402321525442 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8216479 + ... + 9684574.
It is an arithmetic number, because the mean of its divisors is an integer number (321413424570).
Almost surely, 213140232152544 is an apocalyptic number.
13140232152544 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13140232152544 is an abundant number, since it is smaller than the sum of its proper divisors (17715456606176).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13140232152544 is a wasteful number, since it uses less digits than its factorization.
13140232152544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17901212 (or 17901204 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 13140232152544 its reverse (44525123204131), we get a palindrome (57665355356675).
The spelling of 13140232152544 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-two million, one hundred fifty-two thousand, five hundred forty-four".
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