13140404041030 has 32 divisors (see below), whose sum is σ = 28621787628096. Its totient is φ = 4240264833024.

The previous prime is 13140404041019. The next prime is 13140404041109. The reversal of 13140404041030 is 3014040404131.

It is a junction number, because it is equal to n+sod(n) for n = 13140404040986 and 13140404041004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5521176979 + ... + 5521179358.

It is an arithmetic number, because the mean of its divisors is an integer number (894430863378).

Almost surely, 2^{13140404041030} is an apocalyptic number.

13140404041030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13140404041030 is an abundant number, since it is smaller than the sum of its proper divisors (15481383587066).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13140404041030 is a wasteful number, since it uses less digits than its factorization.

13140404041030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11042356368.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13140404041030 its reverse (3014040404131), we get a palindrome (16154444445161).

The spelling of 13140404041030 in words is "thirteen trillion, one hundred forty billion, four hundred four million, forty-one thousand, thirty".