Base | Representation |
---|---|
bin | 10011000111110011000… |
… | …100101010111101010100 |
3 | 11122121202220221112010120 |
4 | 103013303010222331110 |
5 | 133012130014111200 |
6 | 2443355120151540 |
7 | 163636133112561 |
oct | 23076304527524 |
9 | 4577686845116 |
10 | 1314043113300 |
11 | 467312098055 |
12 | 1928064685b0 |
13 | 96bb561cc38 |
14 | 47858685868 |
15 | 242abc229a0 |
hex | 131f312af54 |
1314043113300 has 36 divisors (see below), whose sum is σ = 3801964742016. Its totient is φ = 350411496800.
The previous prime is 1314043113281. The next prime is 1314043113319. The reversal of 1314043113300 is 33113404131.
It is an interprime number because it is at equal distance from previous prime (1314043113281) and next prime (1314043113319).
It is a super-2 number, since 2×13140431133002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2190071556 + ... + 2190072155.
Almost surely, 21314043113300 is an apocalyptic number.
1314043113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1314043113300 is an abundant number, since it is smaller than the sum of its proper divisors (2487921628716).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1314043113300 is a wasteful number, since it uses less digits than its factorization.
1314043113300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4380143728 (or 4380143721 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1314043113300 its reverse (33113404131), we get a palindrome (1347156517431).
The spelling of 1314043113300 in words is "one trillion, three hundred fourteen billion, forty-three million, one hundred thirteen thousand, three hundred".
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