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131412332431440 = 24325182517128377
BaseRepresentation
bin11101111000010011010001…
…011001001100100001010000
3122020021220012101122111210200
4131320103101121030201100
5114211024424100301230
61143253554143255200
736452141050251234
oct3570232131144120
9566256171574720
10131412332431440
1138965725821815
12128a47102aa500
13584318c168268
1424645685dc5c4
15102d50a242160
hex7784d164c850

131412332431440 has 60 divisors (see below), whose sum is σ = 441326416418004. Its totient is φ = 35043288648192.

The previous prime is 131412332431357. The next prime is 131412332431487. The reversal of 131412332431440 is 44134233214131.

131412332431440 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 1 + 2 + 332 + 4 + 314 + 4 + 0 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 41317229911104 + 90095102520336 = 6427848^2 + 9491844^2 .

It is a tau number, because it is divible by the number of its divisors (60).

It is a super-2 number, since 2×1314123324314402 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 131412332431395 and 131412332431404.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 91258563469 + ... + 91258564908.

Almost surely, 2131412332431440 is an apocalyptic number.

131412332431440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131412332431440 is an abundant number, since it is smaller than the sum of its proper divisors (309914083986564).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131412332431440 is a wasteful number, since it uses less digits than its factorization.

131412332431440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 182517128396 (or 182517128387 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 36.

Adding to 131412332431440 its reverse (44134233214131), we get a palindrome (175546565645571).

The spelling of 131412332431440 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred thirty-two million, four hundred thirty-one thousand, four hundred forty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 30 36 40 45 48 60 72 80 90 120 144 180 240 360 720 182517128377 365034256754 547551385131 730068513508 912585641885 1095102770262 1460137027016 1642654155393 1825171283770 2190205540524 2737756925655 2920274054032 3285308310786 3650342567540 4380411081048 5475513851310 6570616621572 7300685135080 8213270776965 8760822162096 10951027702620 13141233243144 14601370270160 16426541553930 21902055405240 26282466486288 32853083107860 43804110810480 65706166215720 131412332431440