Base | Representation |
---|---|
bin | 1011111100111110001110… |
… | …0010011001010100011100 |
3 | 1201112101010002212122201220 |
4 | 2333033203202121110130 |
5 | 3210310031313344400 |
6 | 43541224020533340 |
7 | 2524326021163005 |
oct | 277174342312434 |
9 | 51471102778656 |
10 | 13142122403100 |
11 | 42075a7533789 |
12 | 1583046251250 |
13 | 7443b2180422 |
14 | 3361214921ac |
15 | 17bccb8987a0 |
hex | bf3e389951c |
13142122403100 has 72 divisors (see below), whose sum is σ = 38060721124608. Its totient is φ = 3501231384000.
The previous prime is 13142122403063. The next prime is 13142122403101. The reversal of 13142122403100 is 130422124131.
It is a super-2 number, since 2×131421224031002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13142122403101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20525364 + ... + 21155963.
Almost surely, 213142122403100 is an apocalyptic number.
13142122403100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13142122403100 is an abundant number, since it is smaller than the sum of its proper divisors (24918598721508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142122403100 is a wasteful number, since it uses less digits than its factorization.
13142122403100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41682395 (or 41682388 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13142122403100 its reverse (130422124131), we get a palindrome (13272544527231).
The spelling of 13142122403100 in words is "thirteen trillion, one hundred forty-two billion, one hundred twenty-two million, four hundred three thousand, one hundred".
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