131421451113340 has 24 divisors (see below), whose sum is σ = 280662760007280. Its totient is φ = 51677587555968.

The previous prime is 131421451113287. The next prime is 131421451113341. The reversal of 131421451113340 is 43311154124131.

It is a junction number, because it is equal to n+sod(n) for n = 131421451113296 and 131421451113305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131421451113341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55687054377 + ... + 55687056736.

It is an arithmetic number, because the mean of its divisors is an integer number (11694281666970).

Almost surely, 2^{131421451113340} is an apocalyptic number.

131421451113340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131421451113340 is an abundant number, since it is smaller than the sum of its proper divisors (149241308893940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131421451113340 is a wasteful number, since it uses less digits than its factorization.

131421451113340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111374111181 (or 111374111179 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 34.

The spelling of 131421451113340 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, four hundred fifty-one million, one hundred thirteen thousand, three hundred forty".