13153513304040 has 128 divisors (see below), whose sum is σ = 40109752454400. Its totient is φ = 3449902417920.

The previous prime is 13153513304039. The next prime is 13153513304047. The reversal of 13153513304040 is 4040331535131.

It is a super-3 number, since 3×13153513304040³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13153513303992 and 13153513304010.

It is not an unprimeable number, because it can be changed into a prime (13153513304047) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 160479309 + ... + 160561251.

It is an arithmetic number, because the mean of its divisors is an integer number (313357441050).

Almost surely, 2^{13153513304040} is an apocalyptic number.

13153513304040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13153513304040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20054876227200).

13153513304040 is an abundant number, since it is smaller than the sum of its proper divisors (26956239150360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13153513304040 is a wasteful number, since it uses less digits than its factorization.

13153513304040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103947 (or 103943 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 13153513304040 its reverse (4040331535131), we get a palindrome (17193844839171).

The spelling of 13153513304040 in words is "thirteen trillion, one hundred fifty-three billion, five hundred thirteen million, three hundred four thousand, forty".