Base | Representation |
---|---|
bin | 11000100001000101… |
… | …01010111100010010 |
3 | 1020222022102112020002 |
4 | 30100202222330102 |
5 | 203424040114010 |
6 | 10014032250002 |
7 | 644114530130 |
oct | 142042527422 |
9 | 36868375202 |
10 | 13162426130 |
11 | 5644934627 |
12 | 26740a0902 |
13 | 1319c31839 |
14 | 8cc16a750 |
15 | 5208381a5 |
hex | 3108aaf12 |
13162426130 has 64 divisors (see below), whose sum is σ = 28524960000. Its totient is φ = 4271885568.
The previous prime is 13162426129. The next prime is 13162426217. The reversal of 13162426130 is 3162426131.
It is a junction number, because it is equal to n+sod(n) for n = 13162426093 and 13162426102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2056976 + ... + 2063364.
It is an arithmetic number, because the mean of its divisors is an integer number (445702500).
Almost surely, 213162426130 is an apocalyptic number.
13162426130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13162426130 is an abundant number, since it is smaller than the sum of its proper divisors (15362533870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13162426130 is a wasteful number, since it uses less digits than its factorization.
13162426130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7971.
The product of its (nonzero) digits is 5184, while the sum is 29.
Subtracting from 13162426130 its reverse (3162426131), we obtain a palindrome (9999999999).
The spelling of 13162426130 in words is "thirteen billion, one hundred sixty-two million, four hundred twenty-six thousand, one hundred thirty".
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