Base | Representation |
---|---|
bin | 10011001010000001000… |
… | …000100111000100111100 |
3 | 11122211220212210002220021 |
4 | 103022001000213010330 |
5 | 133032014122213000 |
6 | 2444431303501524 |
7 | 164052136614010 |
oct | 23120100470474 |
9 | 4584825702807 |
10 | 1316424413500 |
11 | 468324298149 |
12 | 19316ba578a4 |
13 | 971a4a8c201 |
14 | 47a02a38540 |
15 | 2439ad0311a |
hex | 1328102713c |
1316424413500 has 48 divisors (see below), whose sum is σ = 3285795344832. Its totient is φ = 451345512000.
The previous prime is 1316424413489. The next prime is 1316424413527. The reversal of 1316424413500 is 53144246131.
It is a super-3 number, since 3×13164244135003 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 188057131 + ... + 188064130.
It is an arithmetic number, because the mean of its divisors is an integer number (68454069684).
Almost surely, 21316424413500 is an apocalyptic number.
1316424413500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1316424413500 is an abundant number, since it is smaller than the sum of its proper divisors (1969370931332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1316424413500 is a wasteful number, since it uses less digits than its factorization.
1316424413500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 376121287 (or 376121275 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 1316424413500 its reverse (53144246131), we get a palindrome (1369568659631).
The spelling of 1316424413500 in words is "one trillion, three hundred sixteen billion, four hundred twenty-four million, four hundred thirteen thousand, five hundred".
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