Base | Representation |
---|---|
bin | 1100000000011001111011… |
… | …1101100001110111100010 |
3 | 1201202000100110022200000120 |
4 | 3000012132331201313202 |
5 | 3212241323431231432 |
6 | 44024300254101110 |
7 | 2531514412506315 |
oct | 300063675416742 |
9 | 51660313280016 |
10 | 13201101430242 |
11 | 422a612672820 |
12 | 15925661aa796 |
13 | 749b2123925b |
14 | 338d184d897c |
15 | 17d5ce675c2c |
hex | c019ef61de2 |
13201101430242 has 64 divisors (see below), whose sum is σ = 30323508848640. Its totient is φ = 3789141163200.
The previous prime is 13201101430229. The next prime is 13201101430327. The reversal of 13201101430242 is 24203410110231.
13201101430242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-4 number, since 4×132011014302424 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6451623 + ... + 8247765.
It is an arithmetic number, because the mean of its divisors is an integer number (473804825760).
Almost surely, 213201101430242 is an apocalyptic number.
13201101430242 is an abundant number, since it is smaller than the sum of its proper divisors (17122407418398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13201101430242 is a wasteful number, since it uses less digits than its factorization.
13201101430242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1802039.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13201101430242 its reverse (24203410110231), we get a palindrome (37404511540473).
The spelling of 13201101430242 in words is "thirteen trillion, two hundred one billion, one hundred one million, four hundred thirty thousand, two hundred forty-two".
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