Base | Representation |
---|---|
bin | 111101011110111101… |
… | …0111001011101010000 |
3 | 110121210202210212020001 |
4 | 1322331322321131100 |
5 | 4130402022234100 |
6 | 140353423455344 |
7 | 12352646656240 |
oct | 1727572713520 |
9 | 417722725201 |
10 | 132035352400 |
11 | 50aa5572556 |
12 | 2170a457554 |
13 | c5b2779173 |
14 | 6567927b20 |
15 | 367b8aad6a |
hex | 1ebdeb9750 |
132035352400 has 120 divisors (see below), whose sum is σ = 366269543360. Its totient is φ = 44802478080.
The previous prime is 132035352373. The next prime is 132035352437. The reversal of 132035352400 is 4253530231.
132035352400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 28531 + ... + 514669.
Almost surely, 2132035352400 is an apocalyptic number.
132035352400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132035352400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (183134771680).
132035352400 is an abundant number, since it is smaller than the sum of its proper divisors (234234190960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132035352400 is a wasteful number, since it uses less digits than its factorization.
132035352400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 486261 (or 486250 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 132035352400 its reverse (4253530231), we get a palindrome (136288882631).
The spelling of 132035352400 in words is "one hundred thirty-two billion, thirty-five million, three hundred fifty-two thousand, four hundred".
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